x6 _ 511x3 - 512 = 0
(x3)2 - 511(x3) - 512 = 0
Let u = x3 Then, u2 - 511u - 512 = 0
(u - 512)(u + 1) = 0
u = 512 or u = -1
So, x3 = 512 or x3 = -1
x = (512)1/3 or x = -1
x = 8 or x = -1
Brown J.
asked 09/02/15
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