ineteger ? again

Question

difference between two integers is 4 - the sum of the two integers is 16 - whites the absolute value of the differences of the squares of the integers?

Answer 1

Take integer 1 to be a. Take integer 2 to be b. So, a-b=4 and a+b=16. These are simultaneous equations. From the first equation, a = b+4. Plugging this into the second equation, 2b+4=16, so b=6. Plugging what b equals into either equation tells you that a must equal 10. Thus, the absolute value of the differences of the squares is: |a^2-b^2|. |10^2-6^2|=64. So, the answer is 64. Notice that the answer is the same no matter the order of a and b, hence the purpose of the absolute value (so there is only one answer to the problem).