solve for x when 4(x+3)=3[x-(2-x)]

Question

I need help solving this problem please...thanks 

Answer 1

4x + 12 = 3x - 6 + 3x

4x + 12 = 6x - 6   (add the 3x's together)

12 = 2x - 6  (subtract 4x from both sides of equation)

18 = 2x  (add 6 to both sides of equation)

9 = x  (divide each side of equation by 2)

 

 

 

Answer 2

Distribute first:

4x + 12 = 3[x - 2 + x]

                        (make sure to distribute the negative, making the 2 negative and the x positive)

Continue distributing on the right:

4x + 12 = 3x - 6 + 3x

Combine like terms:

4x + 12 = 6x - 6

Now put all like terms together on same side:

4x-6x = -6 - 12 (subtract 6x and 12 from both sides)

Combine like terms:

-2x = -18 (same sign, add together and keep the sign)

Divide both sides by -2 to isolate x:

x = 9