college algebra

Question

a total of $65,000 is to be invested, some in bonds some in cds, if the amount in bonds is to exceed cds by $6,000, how much will be invested in each bonds and cd

Answer 1

Hello, thank you for taking the time to post your question!

The key on this type of question is to use the information given in the question in order to set up an algebraic expression that we can solve. On this one we have

B + C = 65000   since there is $65,000 total to be invested between the bonds and CDs

B = C + 6000     since the bond amount exceeds the CD amount by $6,000

I would plug the second equation into the first and then solve for the value of C

C + 6000 + C = 65000

2C = 59000

C = 59000/2 = 29500

Meaning that B = 29500 + 6000 = 35500

So in total the investments are $35,500 in bonds and $29,500 in CDs.

I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

Let x = the amount to be invested in CDs.  The amount invested in bonds exceeds the amount invested in CDs by $6000, so that amount is x + $6000.  The total is $65,000:

 

x + (x + $6000) = $65,000

 

2x + $6000 = $65,000

 

Can you solve it from here?