Caitlin L. answered • 08/16/15
Tutor
New to Wyzant
BS in Chemistry Tutoring Science and Math
The school first sold 3 senior tickets a 1 child ticket for $38, then they sold 3 senior tickets and 2 child tickets for $52. Recognize that the difference between these two sales was just 1 child ticket. This means that 52 - 38 = $14 is the cost of a child's ticket.
From there, let's take the first case. In the first case, we have 3 seniors and 1 child for $38. We just determined that $14 is the cost of a child's ticket, therefore, the cost of all 3 seniors together must be the cost of the sale minus the cost of 1 child's ticket. In other words, 3 seniors + 1 child ($14) = $38. That means that 38-12 =$24. This is the cost of 3 seniors TOGETHER.
From there, let's take the first case. In the first case, we have 3 seniors and 1 child for $38. We just determined that $14 is the cost of a child's ticket, therefore, the cost of all 3 seniors together must be the cost of the sale minus the cost of 1 child's ticket. In other words, 3 seniors + 1 child ($14) = $38. That means that 38-12 =$24. This is the cost of 3 seniors TOGETHER.
If $24 is the cost of 3 seniors together, then each ticket would cost $24 / 3 = $8 per senior ticket
I hope that makes sense. If can re-word anything to make it more clear please let me know.
I hope that makes sense. If can re-word anything to make it more clear please let me know.
