Michael J. answered 08/03/15
Tutor
5
(5)
4+ Years in 2D Sketching and Advanced 3D Modeling Techniques
Some parts of the box has a price per area. Since we have a box with a square base, we need to utilize the surface area and the volume.
Let x = length = width -----> square base
Let y = height
Set up two equations using the variables. One for volume and the other for cost. The cost is affected by the surface area. If we draw the box and label the sides, we can write these equations.
x2y = 250 eq1
C = 2(2x2) + 4xy
C = 4x2 + 4xy eq2
Now the question here is can she construct a box for less than $300? If the dimensions come out to be positive, then she can. If she gets a negative or zero dimension, then she cannot. We use eq2 to solve this problem.
First, we need to get eq2 in terms of one variable. Let have it in terms of x, since we have more x variables.
Substituting eq1 into eq2,
C = 4x2 + 4x(250 / x2)
C = 4x2 + 1000/x
C = (4x3 + 1000) / x
Set C=299
299 = (4x3 + 1000) / x
Multiply both sides of the equation by x.
299x = 4x3 + 1000
Subtract 299x on both sides of the equation.
0 = 4x3 - 299x + 1000
Solve for x from the bolded equation. If the value of x is positive, then she can construct a box.