Air P.

asked • 08/03/15

i do not understand

Use the numbers from the original example: $1,000 invested at a 2% interest rate compounded n times per year. Compare the change in P as n increases. Fill in the table. Use a calculator and write the values to 5 decimal places.

n
1 (once per year) a0
4 (every 3 months) a1
12 (every month) a2
52 (every week) a3
365 (every day) a4

 
p=p0(1+r/n)^n

1 Expert Answer

By:

Laurea D. answered • 08/03/15

Tutor
4.2 (5)

Experienced&Certified Math/Stats Teacher/Tutor

Mark M.

Note the changes in number of calculations for third, fourth, and fifth.
 
Third: p = 1000(1 + 0.02/12)12·2
Fourth p: = 1000(1 + 0.02/52)52·3
Fifth: p = 1000(1 + 0.02/365)365·4
 
A more accurate formula
p = p0(1 + r/n)n·t·, where n = number of calculations per term (usually a year) and t = number of terms
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08/03/15

Mark M.

In simple interest the interest is not added to the amount invested. Only the principal earns interest.
In compound interest the interest is added to the amount and thus also gains interest.
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08/03/15

Laurea D.

Thanks for the corrected exponents :-)
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08/03/15

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