Laura A.

asked • 08/22/13

5/3d-3/2=-1/2

Please show me how to solve and what is the mane of this problem

Roger N.

tutor

Gentlemen:

I think we have to determine whether the problem statement is (5/3d) or (5/3)d. If it is the first then the solution for d is 5/3. If it is the latter then the solution for d is 3/5. I assumed that 5/3d is actually (5/3d) where d is in the denominator of the fraction. However, if it was in the numerator of the fraction such as (5/3)d or (5d/3) it would have been the reverse of my answer or d=3/5. Let us put an end to this argument and stress i=on the importance of presenting the problem statement accurately with proper paranthesis. For next time. we should require more information from the posting student to prevent ambiguity in understanding and solving the problem.

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08/26/13

4 Answers By Expert Tutors

By:

James M. answered • 08/22/13

Tutor
4.6 (76)

James in Louisville, Kentucky

Benjamin K.

This is a syntax error. (5/3)d not 5/3d

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08/22/13

Benjamin K. answered • 08/22/13

Tutor
New to Wyzant

Tutoring in Social Studies, Reading, or basic subjects

Roger N.

tutor

d = 5/3 because 3(5/3d) = 1(3) and  (5/d) = 3 so 5 = 3d and d = 5/3

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08/22/13

Benjamin K.

We are saying the exact same thing.  I solved the problem using the law of fractions while you gave a more algebraic solution.  I did not disagree with your solution because it was also a viable way to solve the problem.  I solved the problem using algebra, but proved the solution using simple mathematics.

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08/22/13

Benjamin K.

Your math is correct, but you are assuming that the student understands why each step you propose is needed.  The object is not to simply solve the problem for the student, but to allow them to solve similar problems themselves.  When you decided that my answer was incorrect what did you base it on?  I combined terms adding 3/2 to both sides of the equation.  this gave me an equation 5/3d=1

I did not need to cross multiply (which confuses some students).  In math it is important that their is only one solution, not only one way to reach the solution.  the more ways a student can learn to solve a problem the more likely they will be to retain the skill.

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08/22/13

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