neutralization question help

Question

write a balanced formula equations for the following acid-base neutralization reaction.

1. A. hydroiodic acid and beryllium hydroxide. 

 

   B. nitric acid and calcium hydroxide

 

2. a 70.0 ml sample of H2SO4 solution neutralized by 256.3 ml of a 0.100 M NaOH solution. what is the molarity of the sulfuric acid (H2SO4)?

Answer 1

1a. 2HI + Be(OH)₂-------> BeI₂ + 2H₂O

 

First you must correctly identify each compound. Hydroiodic is a compound with hydrogen & iodine. Beryllium hydroxide is a compound with beryllium and 2 OH^- ions. Then you must balance the reaction on both sides to preserve mass.

 

B. Nitric Acid - HNO₃

 

    Calcium Hydroxide - Ca(OH)₂

 

2HNO₃ + Ca(OH)₂ --------> Ca(NO₃)₂ + 2H₂)

 

2. H₂SO₄ + 2NaOH ---------> Na₂SO₄ + 2H₂O

 

1 mole of sulfuric acid neutralizes 2 moles of lye

 

Amount of moles of lye = (256.3 ml)(0.1 moles/liter) = .02563 moles

 

There then must be 1/2 the amount of moles for sulfuric acid or .012815 moles

 

(70 ml)(x moles/liter) = .012815 moles

 

.07x moles = .012815 moles

 

x = .183

 

The molarity of the sulfuric acid is .183 M