Ira S. answered 07/27/15
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I would use the basic rule that the divisor*the quotient+remainder=dividend.
That is: if 50/6 =8 remainder 2, then 6*8+2+50.
In your problem, we'd get:
12(X-3) + 1=x2 solving you'd get
12x-36+1=x2
0 =x2-12x+35
0 =(x-5)(x-7)
0=x-5 or 0=x-7
x=5 or x=7
Let's check x=7.... 49/4=12 R1
let's check x=5.....25/2=12 R1
So both answers work!!!!!!!
Hope this helped.