Inactive Tutor answered 08/20/13
Arlandria, you have to use parentheses for this kind of problem, or use the bar notation to avoid the double reading!!
(2x - 3) / (x + 1) = 2 - (3x - 1) / (x + 1)
or
2x – 3 3x – 1
———— = 2 – ————
x + 1 x + 1
2x – 3 3x – 1
————— + ———— = 2
x + 1 x + 1
2x – 3 + 3x – 1
————————— = 2
x + 1
5x – 4
———— = 2
x + 1
5x – 4 = 2(x + 1)
5x – 4 = 2x + 2
5x – 2x = 4 + 2
3x = 6
x = 2
Inactive Tutor
Just one question: how did you figure out it is (2x-3)/(x+1), not 2x-3/(x+1), for example??
08/20/13