Write an equation fort he line through the point (-1,2) and parallel to the line with equation 3x-2y-5=0. Write the equation in the general form.

**We know that parallel lines have the same slope**. Therefore, the line we are drawing will have the same slope as the equation 3x - 2y - 5 = 0.

However, to find the slope the equation must be in the form of: y = mx + b, where m = slope and b = y intercept.

3x - 2y - 5 = 0

2y = 3x - 5

y = (3/2)x - (5/2)

**So, the slope of the line is: m = 3/2**

**We now know two pieces of information about the line, the slope is 3/2 and it goes through the point (-1, 2). Use the equation for point slope to generate the equation of our line:**

(y - y_{1}) = m (x - x_{1}),

where m = 3/2, x_{1} = -1, y_{1} = 2

(y - 2) = (3/2) (x - (-1))

y - 2 = (3/2)x + (3/2)

y = (3/2)x + (7/2)

**Answer: y = (3/2)x + (7/2)**