
David W. answered 07/18/15
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You are learning the rules for solving an inequality:
(1) you may add or subtract the same amount from both sides without changing the inequality, but
(2) if you multiply or divide by a positive value, it maintains the sense of the inequality, and
(3) if you multiply or divide by a negative value, it reverses the sense of the inequality.
Given: 7−2/b<5/b
7 < 7/b (add 2/b to both sides)
1 < 1/b (divide both sides by +7)
Now, be careful -- we don't know whether b is positive to negative.
b < 1 if b is positive (multiply both sides by b)
b > 1 if b is negative (multiply both sides by b)
(p.s., did you notice the word "solutions" in the problem statement?)
So, let's pick some values and check.
For b=2 (a convenient choice), is 7-2/2 < 5/2 ?
6 <5/2 ? No. Good! 2 is outside our solution range.
For b=-2 (another convenient choice), is 7-2/(-2) < 5/(-2) ?
8 < -5/2 ? another No. Good!
Well, we can't test 0 because we would have to divide by 0.
For b=1, is 7 -2/1 < 5/1 ?
5 < 5 ? No, but then b=1 also is outside our solution range (we don't allow equal 1 or -1)
O.K., let's test 1/2. is 7 - 2/(1/2) < 5/(1/2) ?
7 - 4 < 10 ? Yes!
And, lastly, test -1/2: Is 7 - 2/(-1/2) > 5/(-1/2) ? (careful, b is negative, so use ">")
7 + 4 > 10 ? Yes!
p.s., This exercise will come in very handy when you work with absolute value inequalities.
Kara G.
07/18/15