Comparing Solvent Effects on SN1 and SN2 Reactions

Question

The major product of the synthesis, 3-methoxyheptane, is produced by an SN2 mechanism. Complete the reaction mechanism by adding curved arrows showing electron flow and the final product, including the correct stereochemistry, to demonstrate the formation of the major product (3-methoxyheptane).

Answer 1

Where do the solvent effects come in related to your question?

 

I don't think you're giving us enough information. 

 

Barring that, Roger F. has answered your question regarding the Sn2 mechanism. Methoxide is such a strong nucleophile and chloride such a good leaving group that the Sn2 mechanism will dominate in this reaction.

Answer 2

What's the reaction? Is it CH₃CH₂CH(Cl)CH₂CH₂CH₃ + CH₃ONa ?

 

If so, you'd show a curved arrow from the CH3O^-  oxygen to C-3 on the substrate, simultaneously with another curved arrow from the bond between C-Cl going on to the Cl. Then the product shows a completed bond between the CH₃O-C and Cl^- having come off as chloride.

 

S_N2 mechanisms produce inversion of configuration, so if you had the R-enantiomer (or S) to start with, you'd get the S-enantiomer (or R) at the end.