Assuming that the roots of the quadratic equation of 3x^2+7x-6=0 are alpha and beta, obtain the the sum and product of the roots

Question

This is a problem which involves with alpha and beta.

Answer 1

Note:  Math uses lots of Greek letters.  Algebra 2 in a great time to Google (or Bing or other) search for a printable Greek upper-and-lower-case alphabet to print (or save on your computer) so that you can quickly identify any letter.
 
Using the quadratic formula, the two roots of the equation, 3x^2+7x-6=0, are 2/3 and -3.
 
I'll assume that it does not matter which is alpha and which is beta, but if the problem had said "larger," "integer," or other clue, than you should be careful to assign them correctly.
 
The sum of 2/3 and -3 is  -2 1/3.
The product of 2/3 and -3 is  -2.
 
Extra note:  If you use A, B, and C in the quadratic equation and add the two roots (the "+" one and the "-" one), you will get these results:   (1) the sum of the roots is -B/A, and (2) the product of the roots is C/A.   Remember that, it will come in handy later!

 

Footnote:  That Andrew M. guy is pretty sharp!  He has found typos and more serious errors in my posts.  Note:  I've just reported to WyzAnt that I cannot edit Comments and, though I can edit Answers, subsequent edits revert to my original answer so that intermediate edits are lost.  Truly, I had corrected this before Andrew found it, but THX for finding it reverted.

Answer 2

Ax² + Bx + C = 0, then the sum of the roots is -B/A and the product of the roots is C/A

 

So, for 3x² + 7x - 6 = 0, sum of roots = -7/3                                                                           product of roots = -6/3 = -2

 

So, α + β = -7/3 and αβ  = -2