Selam N. answered 07/12/15
Tutor
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Mathematics Teacher
(x3 - y3 )/ (x2 + 2xy + y2 ) ÷ [(x - y)(x +y)]
If this is how the question was given to you, here is how you solve it:
- There are two divisions, let us simplify [(x2 - y2 )/ (x2 + 2xy + y2 )] · [1/(x - y)(x +y)]
- Factor the expressions on the left [(x -y)( x2 + xy + y2 )/ (x + y)2][1/(x - y)(x +y)]
- (x - y) is a factor that can be eliminated [( x2 + xy + y2 )/ (x + y)2 ][1/(x +y)]
- Multiply and simplify ( x2+ xy + y2 )/ (x + y)3