Edward C. answered 07/09/15
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If you were to choose a group of six from 30 people with no constraints you could do it in 30C6 ways, where
30C6 = 30!/(6!*(30-6)!)
If you are going to require that 1 player be in all the groups, then that means that you are going to choose the other 5 people in the group from the 29 remaining people, which can be done in 29C5 ways.