which equations represents one of the steps of solving 6x^(2)-6x-12=0 by factoring

Question

a. 6x+2=0 or x-6=0

b. 2x-2=0 or 3x+6=0

c. x-2=0 or x+1=0

d. 6x+4=0 or x-3=0

Answer 1

6x² - 6x - 12 = 0  

Can be divided through by 6 since each term contains a multiple of 6. 

This will make the numbers smaller and easier to deal with.

We now have:
x² - x - 2 = 0

Next we can factorize this expression:

(x+1)(x-2) = 0

To find the solutions we need to solve the following equations:

(x+1) = 0 and (x-2)=0

So, the answer to the question is c)

 

 

Answer 2

The Answer is : (C)

                                         6 x ²-6 x-12=0 ------------------1)

By factorizing  equation 1)  , we will get:

                                         (6 x - 12) (x+1)= 0

                   then  6 x-12 = 0   or (x+1)=0  --------------------2)

                       by dividing the left equation in 2) by 6, we will have:

                                     x-2=0---> x=2       one of the solutions of equation 1)       

                           As (x+1)= 0  ---> x=-1       the second solution of equation 1)