
Andrew M. answered 07/04/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Let V = #students per van Let B = #students per bus
We know from high school A that: 10V + 15B = 945 eqn 1
We know from high school B that: 3V + 13B = 717 eqn 2
We have 2 simultaneous equations with 2 variables... Let's multiply
eqn 1 by 3 and eqn 2 by -10... In this manner we can add the
2 equations and eliminate the variable V in order to solve for B
30V + 45B = 2835 3(eqn 1)
-30V -130B = -7170 -10(eqn 2)
-------------------------
-85B = -4335
B = -4335/(-85) = 51
Each bus held 51 students
Plug the value 51 in place of B in one of the original equations to solve for V
3V + 13B = 717
3V + 13(51) = 717
3V = 717 - 663
3V = 54
V = 18
Each Van held 18 students