
Michael W. answered 07/01/15
Tutor
New to Wyzant
CA Credentialed Teacher .. Multiple Subjects.. verify at CTC.CA.GOV
While the posted answer is not incorrect, it is not the best way to solve the problem. Why use 2 variables and a system of equations when you could simply use one variable and one equation!!!
Let P = pounds of peanuts;
since we know there is 100 pounds of the mixed nuts, if p = lbs of peanuts then.....
(100 - p)= lbs of walnuts so....
(price of peanuts * lbs of peanuts) + (price of walnuts * lbs of walnuts) = total price which can be written as...
1.49 P + 2.69 (100 - P) = 221 (now solve for p)
1.49 P + 269 - 2.69 P = 221 (distribute and combine like terms)
269 - 221 = 2.69 P - 1.49 P (get the variable terms on one side of equation/other terms-other side)
48 = 1.2 P simplify and solve
48/1.2 = P
40 =p
And, if there are 40 lbs of peanuts, there must be 60 lbs of walnuts!
Andrew M.
07/01/15