Stephanie M. answered 06/13/15
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Let c = tons of CCC cheese, s = tons of SSS cheese, and b = tons of BBF cheese. You can write a system of equations to solve this problem:
c + s + b = 100
80c + 50s + 65b = 5810
c = b
Substitute the third equation into the first equation for c. Then, solve the first equation for s. Plug that expression for s into the second equation, and plug the third equation into the second equation for c as well. You should be able to solve for b, which equals c, and use that information to solve for s.