Philip P. answered 06/11/15
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By counting outcomes: P(F or G) = n(F or G)/n(S)
- n(S) = 12
- n(F) = 4
- n(G) = 3
- n(F and G) = 0 (Sets F and G do not intersect)
- n(F or G) = n(F) + n(G) - n(F and G) = 4 + 3 - 0 = 7
- P(F or G) = n(F or G)/n(S) = 7/12
Using the general addition rule: P(F or G) = P(F) + P(G) - P(F and G)
- P(F) = n(F)/n(S) = 4/12
- P(G) = n(G)/n(S) = 3/12
- P(F and G) = n(F and G)/n(S) = 0/12 = 0
- P(F or G) = 4/12 + 3/12 - 0 = 7/12