Inactive Tutor answered 06/07/15
Tutor
New to Wyzant
a•b
cos(θ) = ---------------- and a = (1/2)c and b = -5c
||a||·||b||
(1/2)c • (-5)c
so θ = arccos(--------------------)
||(1/2)c||·||-5c||
(-5/2) c•c
= arccos(---------------)
(5/2) ||c||2
= arccos(-1)