
Nathan B. answered 05/26/15
Tutor
5
(20)
Elementary and Algebraic skilled
Let's ID our variables. s = small dogs, l = large dogs
Here's what we know:
s + l = 8
5s + 8l = 55
Since we need to use elimination, what we need to do is multiply the first equation by an amount that will get rid of a variable. I suggest -5 and get rid of the s. (-8 also works to get rid of the l if you so desire.)
-5s - 5l = -40
5s + 8l = 55
------------------
3l = 15
Divide both sides by 3:
l = 5
Now we can solve for small dogs:
s + 5 = 8
s = 3
Now to check our answer:
5 * 3 + 8 * 5 = 55
15 + 40 = 55
55 = 55