Pranav N.

asked • 05/26/15

prove that the circle bisects the base

if it is drawn on anny one of the equal sides of an isosceles triangle as diameter

Mitiku D.

If one of the legs is a diameter, the other leg is definitely not going to reach the circle. This means that the base is completely inside the circle and the idea of the circle bisecting the base is meaningless. May be you are missing some information.
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05/26/15

Mark M.

If one leg is a diameter, the other leg shall be a secant of the circle. Since the diameter is the largest chord of a circle, the second leg (secant) shall meet the base outside of the circle. Where this intersection is depends on the length of the base. Changing the length of the base (or the size of the unequal angle) changes the location of the midpoint of the base.
 
Too many variables to develop of proof.
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05/26/15

1 Expert Answer

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Andrew D. answered • 05/26/15

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A line drawn through the points of intersection of two circles whose diameters are the equal sides of an isosceles triangle
will bisect the base.  We can guarantee that there are two points of intersection.  Is this what you need to prove?
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Mark M.

The line joining the centers shall bisect the base (shared) of the two triangles. The line joining the points of intersection is the base.
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05/26/15

Andrew D.

There is only one triangle.  One point of intersection of the two circles is the apex.  The line joining the points of intersection is not the base.  Tough to explain without a diagram.
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05/26/15

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