The perimeter of a rectangle is 132 meters. The length is 6 meters longer than twice the width. Find the dimensions

Question

word problem/ find width

Answer 1

The perimeter is represent by the formula

 

P = 2(length) + 2(width)

 

Assign variables for the length and width.

 

Let width = x

Let length = 2x + 6

 

 

Set up an equation using the formula for perimeter.

 

2x + 2(2x + 6) = 132

 

Now we can solve for x.

 

2x + 4x + 12 = 132

6x + 12 = 132

6x = 120

  x = 20

 

Substitute this value of x into the length and width.

 

width = 20

length = 2(20) + 6 = 40 + 6 = 46

 

 

The width is 20 meters.

The length is 46 meters.

Answer 2

First you have to label your rectangle with the width being "x" and the length being "2x+6" since it is 6 meters longer than twice the width.

 

In perimeter you add up all the sides, so it is "x+x+2x+6+2x+6."  Combining like terms gives you "6x+12".

 

6x+12=132

6x=120

x=20

 

So the width is 20 meters.  To find the length, just plug in the width to the "2x+6" for the length.

 

2x+6

2(20)+6

40+6

46

 

In order to check the perimeter, add up all the sides.

 

20+20+46+46= 132.

 

Therefore, the rectangle has dimensions of 20 meters by 46 meters.