
Andrew M. answered 05/21/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
(6x^3 + 5x -8) / (x-2)
Set up like a regular division problem. In each case you will multiply the x term of (x-2)
by whatever value will make it equal to the first term in the appropriate line then subtract from
the previous line.
6x2 + 12x + 29
__________________________
(x-2) / 6x3 + 5x -8
-(6x3 -12x2) Note (6x2)(x-2) = 6x3-12x2
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12x2 + 5x -8
-(12x2 -24x) Note (12x)(x-2) = 12x2-24x
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29x - 8
-(29x - 58) Note (29)(x-2) = 29x - 58
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50
Stop at the point where the difference has a lower exponent than the divisor and write
the remainder as R/(x-2)
(6x^3 + 5x -8) / (x-2) = 6x2 + 12x + 29 + 50/(x-2)