Jacob M. answered 05/11/15
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Math PhD & software engineer who loves teaching
Since she is placing them in a bag, the order doesn't matter, so this is a combinations problem. Therefore, the answer is
9C5
Calculate this.
9C5 = 9!/(5!(9-5)!)
= 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 / (5 x 4 x 3 x 2 x 1 x 4 x 3 x 2 x 1)
A bunch of cancellations occur. Can you take it from here?
Regards,
Jake