Edward C. answered 05/11/15
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Caltech Grad for math tutoring: Algebra through Calculus
Let X be the width of the border around the picture.
The border is on all 4 sides (top and bottom, left and right) so the total size of the photograph plus border is
(14 + 2*X) by (20 + 2*X)
This area is 352 so
(14 + 2*X)*(20 + 2*X) = 352
280 + 40*X + 28*X + 4*X2 = 352
4*X2 + 68*X - 72 = 0
X2 + 17*X - 18 = 0
(X + 18)*(X - 1) = 0
X = -18 or X = 1
The border cannot have a negative width so discard X = -18
The border will be 1 cm wide
Check: (14 + 2)*(20 + 2) = 16*22 = 352