Use the Laws of logarithms to rewrite the expression

Question

log((x^3 y^8)/z^10)

Alog(x)+Blog(y)+Clog(z)

 

A=

B=

C=

Answer 1

log ((x³ y⁸)/z¹⁰) 

= log (x³ y⁸) - log (z¹⁰)               (by the law for logarithm of a quotient)

= log x³ + log y⁸ - log z¹⁰               (by the law for logarithm of a product)

= 3 log x + 8 log y - 10 log z        (by the law for logarithm of a power)

 

So,

 

A = 3

B = 8

C = -10