Stephanie M. answered 04/30/15
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For this question, you can use the Multinomial Theorem (a version of the Binomial Theorem for three or more terms). Or, you can group the terms (as in, ((x+y) + z)n) and apply the Binomial Theorem as usual.
For example, (x+y+z)3 = ((x+y) + z)3 = (x+y)3 + 3(x+y)2z + 3(x+y)z2 + z3
Then, expand the (x+y) terms using the Binomial Theorem:
(x3 + 3x2y + 3xy2 + y3) + 3(x2 + 2xy + y2)z + 3xz2 + 3yz2 + z3