
Tamara J. answered 05/21/13
Math Tutoring - Algebra and Calculus (all levels)
Vertices: (1, 1) and (5, 1)
Foci: (-1, 1) and (7, 1)
Notice that the vertices and the foci all have the same y-coordinate (that being 1) which means that the transverse axis is horizontal. The standard form for the equation of a hyperbola with a horizontal transverse axis is as follows:
(x - h)2/a2 - (y - k)2/b2 = 1
where the center of the hyperbola is at the point (h, k), the vertices of the hyperbola are at the points (h+a, k) & (h-a, k), and the foci of the hyperbola are at the points (h+c, k) & (h-c, k)
Vertices: (1, 1) = (h+a, k) ==> h + a = 1 ==> h = 1 - a
(5, 1) = (h-a, k) ==> h - a = 5 ==> h = 5 + a
1 - a = 5 + a ==> 1 - a + a - 5 = 5 - 5 + a + a
==> -4 = 2a ==> -4/2 = 2a/2
==> -2 = a ==> (-2)2 = 4 ==> a2 = 4
Foci: (-1, 1) = (h+c, k) ==> h + c = -1 ==> h = -1 - c
(7, 1) = (h-c, k) ==> h - c = 7 ==> h = 7 + c
-1 - c = 7 + c ==> -1 - 7 - c + c = 7 - 7 + c + c
==> -8 = 2c ==> -8/2 = 2c/2
==> -4 = c ==> (-4)2 = 16 ==> c2 = 16
To find b, use the following equation: a2 + b2 = c2
==> b2 = c2 - a2 ==> b2 = (-4)2 - (-2)2 = 16 - 4 = 12
==> b2 = 12 ==> b = √12
Since the center is at (h, k) and all the y-coordinates are the same, this means that k = 1
To find h, use one of the equations we solved for h and plug in the missing variable:
h = 5 + a , a = -2 ==> h = 5 + -2 = 5 - 2 = 3
OR
h = 7 + c , c = -4 ==> h = 7 + -4 = 7 - 4 = 3
Therefore, h = 3
Given the standard form of the equation at the top of the page, we can plug in all missing variables we solved for:
(x - 3)2/4 - (y - 1)2/12 = 1