How can I factor with this parentheses, do I have to multiply? Or do I need to substitute with the parentheses

2x^2(5-y)+7x(y-5)+5(5-y) rewrite this by pulling out negative sign from the middle term

2x^2 (5-y) - 7x (-y+5) + 5 (5-y) rewrite it again for middle term so all the bracket terms look same

2x^2 (5-y) - 7x (5-y) + 5 (5-y) Now pull out the common term that you see for every term GCF

(5-y) (2x^2 -7x + 5) Factor the trinomial

(5-y) (2x - 5) (x-1) ANSWER