Jessica G.

asked • 04/28/15

Prove the identities vsecx- tanx/secx+tanx = 1/secx+tanx

help me 

Jon P.

tutor
The way you've written this is unclear.  There seem to be a lot of missing parentheses.  And does "v" mean square root?  If so, what exactly is it the square root of?  (Again, use parentheses.)
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04/28/15

Jessica G.

(squrtsecx- tanx/secx+tanx) = (1/secx+tanx)
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04/28/15

Stephanie M.

tutor
Hi Jessica,
 
Your formula is still very unclear. Right now, you've written:
 
√(secx) - tanx/secx + tanx = 1/secx + tanx
 
That means that only the secx is under the square root, that only the first tanx is in the numerator of the fraction on the left-hand side and that only the second secx is in the denominator of the fraction on the left-hand side, and that only the secx is in the denominator of the fraction on the right-hand side.
 
You'll need to surround the quantity under the square root sign with parentheses, surround the numerator of both fractions with parentheses, and surround the denominator of both fractions with parentheses.
 
For example, you might write:
 
(√(secx - tanx)) / (secx + tanx) = (1) / (secx + tanx)
 
which means:
 
(√(secx - tanx)) / (secx + tanx) = 1 / (secx + tanx)
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04/29/15

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