Raymond B. answered 08/19/21
Math, microeconomics or criminal justice
200 apples on a tree, yield 500 apples for the season
add another tree and each tree yields 9 less or 491 apples per tree for the season
Yield = 500 + (500-9)T where T=additional trees
Y = 500 +491T
1 more tree means Y=(500-9)x2
2 more trees means Y= (500-9(2))x3
3 more trees means Y= (500-3(9))x4
n more trees means Y= (500-n(9))x(n+1)
Y= (500-9n)(n+1)
=500 -9n+500n -9n^2
= -9n^2 +491n + 500
take the derivative and set = 0
-18n +491 = 0
18n=491
n= 491/18= 27.2727... = about 27 more trees to maximize apples
Y = (500-9n)(n+1) = 500-9(27))(27+1) = 257(28) = 7,196 apples= maximum output of apples with 27 more trees