Richard P. answered 04/14/15
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The easiest way is to write your expression in the form f(x) / g(x) with f(x) = e1/x -1 and g(x) = 1/x.
Then L'Hospital's rule says to replace f/g with f'/g' (where prime denotes derivative) and study the result.
f'/g' = (-1/x2) e1/x and g' = -1/x2 , so f'/g' = e1/x
Since exp is a smooth function, limx=>∞ e1/x = exp(limx=>∞ 1/x) = exp(0) = 1