The zeros of P(x)=x^2+1 x + 3 are

Question

x^1 =____+_____ i with negative imaginary part

x^2=____+_____ i with positive imaginary part

 

Answer 1

P(x) = x² + x + 3

 

The zeros occur when P(x) = 0:

 

0 = x² + x + 3

 

Use the quadratic formula to solve:

 

x = (-1/2) ± (1/2)√(1²-4(1)(3))

x = -1/2 ± (1/2)√(-11)

 

x = -1/2 + (1/2)√11 i

x = -1/2 - (1/2)√11 i