
Patrick W. answered 04/11/15
Tutor
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High School Mathematics Teacher, Passionate Math Geek
width: W
length: L
Area: A=W×L
Perimeter: P= 2W + 2L
L=W+4
A=96=W×L=W×(W+4)
96=W2+4W
W2+4W-96=0
To solve this quadratic, I would recommend something I call the product sum method, where I find factors of a×c which sum to b. In this case,
1×(-96)=-96
-96=12×(-8)
12+(-8)=4
So I'm going to split my middle term into 8-12, which doesn't change anything but is convenient for factoring
W2+4W -96=0
W2+12W-8W-96=0
W(W+12)-8(W+12)=0
(W-8)(W+12)=0
The zero product property here says that W must be either 8 or -12, but we cannot have a distance dimension which is negative.
So W=8, which means L=12, which means
P=2W+2L=16+24=40