
Mark H. answered 04/07/15
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We start by assuming that getting cut is a completely random process---just like flipping a perfect coin or a perfect 6-sided die.
We observe that he cuts himself 36 out of every 200 shaves. Thus, the probability of cutting on any single day is 36 / 200 = 0.18 (18%)
From this the probability of NOT cutting himself is 0.88 (The probability of all possible outcomes must add up to 1)
For random events, the probability of getting N occurrences is the probability of EACH occurrence raised to the Nth power. Example, flipping a coin---probability of heads is 0.5, so 2 heads in a row is 0.5^2 = .25
The probability of 3 cuts in a row: 0.18^3 = 0.00583
The probability of 31 days of NO cuts is the 31st power of the probability of ONE day with no cuts