g(n)=3n-5 f(n)=n^2+2


Optimization Question.

Given y = sinx find the local max/mim on [0,2pi] and the concavity.

Find the exact values (precalc)

Find the exact values (fractions) for the trigonometric expression given that sin u = 4/5 and cos v = -7/25 (both u and v are in II quadrant)

Help!!! Just Need the Need Help with Graphing!

A pipe needs to run from a water main, tangent to a circular fish pond. On a coordinate plane, construct the circular fish pond at a given location and specify your center point and radius. Write... more

Calculus 1- Concave up or down and inflection

Find where the following function is concave up and where it is concave down. Where are the inflection points of the function? f(x) = cos(2x)


Evaluate the function if it is continuous.


function composition

If f(x) = x2 + 5x + 6 and g(x) = x + 2i need help finding and simplifying F(g(2)) G(f(-1)) F(g(0)) (f(g(-4)) G(f(x)) F(g(x))


Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ 𝜃 ≤ 2𝜋.

Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ 𝜃 ≤ 2𝜋. (a)    (7, −7 3 (r, 𝜃) = (b). (8, 8)(r, 𝜃) = 


Differentiate using the quotient rule

Differentiate using the quotient rule d/dx[(cos x)/x].


Can you delete questions off of Wyzant?


completely factor the following expressions



Homework help

A projectile follows a parabolic path whose height, in meters, is given by the function f(x) =-x2 +2x+2. Find the maximum horizontal distance that the projectile may cover


Which graph represents the solutions to the inequality |5x - 10|the sign is greater or equal to 15?

Please help fast I will be really happy thank you.


Find the answer... k=

The half-life of radium is 1600 years. If the initial amount is q0 milligrams, then the quantity q(t) remaining after t years is given by q(t) = q02kt. Find... more


Divide and solve


Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.


Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.