09/08/23
Trignometric Limits
What is the limit of (cos^2 (x))/(1+cos2x)(2+cos2x) as x approaches pi/2
05/21/23
Function Operations
Given f(x)=2x2-3x+1 and g(x)=3x+4, find the following:1.) (f+g)(x)2.) (f-g)(x)3.) (g-f)(x)4.) (f•g)(x)5.) (f/g)(x)6.) (g/f)(x)
04/19/23
PRECALCULUS HELP
Suppose that sec α= −5/3 and π/2 < α < π.Find the exact values of cos α/2 and tan α/2.
cos α/2
=
tan α/2
=
x+3y=18 and y=2x-1
Solve in slope-int form. Please show work. NEED HELP BADLY
Expand the logarithmic expression
Expand the following log(x2y3/z4)
08/05/22
need answer to this asap
Given the function f(x)=1+7x^2 calculate the following values:f(a)= f(a+h)= f(a+h)−f(a)/h=
08/03/22
Simplifying Complex Fractions
Evaluate the expression and write the result in the form of a + bi. 4/1 + i - 4/1 - i
Composition of functions
f(x)=3-2xg(x)= x2-2x-9Find (f o g(3)) and (g o f(3))
Solve the logarithmic equation
Solve the logarithmic equation log3(x-2)=4
Solve the quadratic equation by completing the square
Solve x2+10x+16=0
02/17/22
Can find the exact value of each of the remaining trigonometric functions of θ if sin θ=4/5, 90*<θ<180* ?
cos θ =
csc θ =
tan θ =
cot θ =
01/26/22
Equation Of The Slope
Find the equation of the line with Slope = 2 and passing through (5,15). Write your equation in the form y=mx+b.y =
12/11/21
𝑔(𝑥)=√𝑥+2 +1
𝑔(𝑥)=√(𝑥+2) +1a.) Graph: b.) Is it a function? c.) Is it one-to-one?d.) Domain:e.) Range:Hello! I need help with these problems thank you!
11/13/21
Verify the Trigonometric Identity
Verify the Trig Identity(sin2θ-1)/(tanθsinθ-tanθ) = (sinθ+1)/(tanθ)
11/12/21
What is the Elimination Guided Solution to the description BELOW?
? (-x +2y =-23)? (2x +2y =4) -x +2y =-23 2x =2y = 4?x + ? y =
11/12/21
Simplify the expression
7 over n - 5 + n over n + 5 (Simplify your answer. Type your answer in factored form)The answer I got is n2 + 2n + 35 over (n + 5)(n - 5)Would that be correct?
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.