John G.
asked 02/21/24implicit differential equations
Given the differential equation dy = e^x · sin( y), verify that a given implicit solution dx
satisfies the ODE. Then, find at least one explicit solution y = φ(x) and use a graphing utility to visualize it.
Part A: (10 pts) Verify that an implicit solution of the form F(x , y) = C, where F(x , y) involves an integration of e^x · sin( y), satisfies the differential equation.
Part B: (10 pts) Find an explicit solution y = φ(x) for a specific initial condition, such as y(0) = 4π . Note: If the equation is not easily solvable for y explicitly, discuss the challenges involved.
Part C: (10 pts) Use a graphing utility to graph the solution, whether implicit or parameterized if explicit is not feasible. Analyze the behavior of the solution over an interval
I and discuss any interesting characteristics or patterns observed.
I have the PDF if anything i can send just please reach out to me asap
1 Expert Answer
A) If we have
dy/dx = e^x * sin(y)
we can separate the variables and then integrate to get an implicit solution. Doing that gives
dy/sin(y) = e^xdx
Integrating gives us
ln |csc(y) - cot(y)| = e^x + C
Verifying that the solution exists just means doing the opposite of what we just did by taking the derivatives of both sides and seeing if we get y' = e^x * sin(y), which in this case will give us that answer.
B) Notice that if we plug in x = 0 and y = 4π to the implicit solution, we will get undefined answers.
The trick with this equation is that it is difficult to solve for y when there are two different trigonometric functions inside on a natural logarithm. It would be best solvable by graph, but here is an explicit solution that is valid.
y(x) = 2cot^-1(e^(C - e^x))
C)
y' = e^x * sin(y) - Wolfram|Alpha (wolframalpha.com)
Here's a vector field of the differential equation. A solution can be made for any x or y value by tracing a line following the vectors of the field. From this you can pick an interval, find the value of C in the explicit form, and impose the solution graph on to the vector field.
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Wondwosen L.
05/11/24