Help provide resulting products for given reactions

Question

Please assist in giving pointers for oroducts of the reactions in the attached image:

https://ibb.co/cX3gz5C

Answer 1

(a) CH₃MgBr adds twice to an ester to give a 3° alcohol.

Reason: the ketone that forms after CH₃MgBr displaces ⁻OCH₂CH₃ is more reactive than the ester it is formed from, so it reacts again. (Two equivalents of CH₃MgBr should be used for all of the ester to react.)

(b) Might be intended as DIBAH reduction of an ester to an aldehyde, but the first step should be at –78 °C.

Possible (though unlikely) that it's a trick question and the answer is a 1° alcohol (which is what would actually happen if the first step were carried out at a higher temperature.)

(c) Amine reacts with acyl chloride to produce an amide (O=C–NH linkage), but ½ of the amine gets converted to CH₃CH₂NH₃⁺ so 2 equivalents of CH₃CH₂NH₂ should be used for the reaction.

(d) Acid catalyzed reaction of CH₃OH with a carboxylic acid to form a methyl ester.

(e) LiAlH₄ reduces an ester to a 1° alcohol (CH₃OH also formed).

(f) The alcohol PhCH₂CH₂OH reacts with (CH₃CO)₂O (acetic anhydride) to produce an acetate ester

PhCH₂CH₂O–COCH₃.

(g) The amide (–O=C–NH₂) in the molecule gets reduced to an amine (–CH₂–NH₂) by LiAlH₄.

(h) The reagent SOCl₂ converts a carboxylic acid (R–CO₂H) to an acyl chloride ((R–COCl).

(OH is replaced by Cl.)