find the equation of the line in slope intercept form perpendicular to 5x-4y=3 and goes through the point (15,1)

Question

find the equation of the line in slope intercept form perpendicular to 5x-4y=3 and goes through the point (15,1)

Answer 1

5x - 4y = 3

-4y = -5x + 3 So, y = (5/4)x - 3/4 (slope = 5/4)

Perpendicular line slope = -1 / (5/4) = -4/5

Equation of perpendicular line: y - 1 = -(4/5)(x - 15)

So, y = -(4/5)x + 13