William C. answered 10/05/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
Keq = e–ΔG/RT
T = 25 °C = 298 K,
ΔG = 9.2 kJ/mol = 9200 J/mol
R = 8.314 J/mol-K
ΔG/RT = (9200 J/mol)/(8.314 J/mol-K)(298 K) = 3.7133
Keq = e–3.7133 ≈ 1/40.99
Answer (rounded to 2 significant figures)
The ratio of concentrations of the two conformations
[axial conformer]/[equatorial conformer] = 1/41