
Yefim S. answered 10/02/23
Math Tutor with Experience
A'(t) = 6 - A(t)/60;
A'(t) + 1/60A(t) = 6; M = e∫1/60dt = et/60; A'(t)et/60 + 1/60A(t)et/60 [= 6et/60; d/dt(et/60A(t)) = 6et/60;
A(t)et/60 = ∫6et/60dt; A(t) = 360et/60 + C; A(t) = 360 + Ce-t/60;
At t = 0 A(0) = 50; 50 = 360 + C; C = - 310; A(t) = 360 - 310e-t/60g