Yefim S. answered 09/25/23
Math Tutor with Experience
∫(e7y - ye-y)dy = ∫tan6tdt; e7y/7 + ye-y + e-y = - ln(cos6t)/6 + C; 1/7 + 1 = C; C = 8/7;
e7y/7 + ye-y + e-y = - ln(cos6t)/6 + 8/7. Let t = t0. Then e7/7 + 2/e = - ln(cos6t0 + 8/7;
ln(cos6t0) = - (e7/7 + 2/e - 8/7) = - 156.2548