Chonky S.

asked • 09/24/23

Solve the given differential equation.

dx/dt =(9/(xe^(11x+t))


Let x(t) be the solution with initial value x(0) = 1. If t0 = (-ln(10/1089)e^11+1), find the value of x (t0) with the answer rounded to exactly 4 digits after the decimal point.


1 Expert Answer

By:

Jonathan T. answered • 09/24/23

Tutor
5.0 (362)

Calculus, Linear Algebra, and Differential Equations for College

Matthew K.

The approach that you have outlined, with respect, appears to me to contain a few errors and discrepancies. 1. Identification of ODE: The statement correctly identifies the differential equation as a first-order separable ODE. 2. Separation of Variables: The solution attempts to separate variables correctly but appears to have made an algebraic mistake when writing \( \frac{dx}{dt} = 9xe^{11x+t} \) as \( \frac{dx}{dt} = 9xe^{11x}e^t \). The original equation is \( \frac{dx}{dt} = \frac{9}{x e^{11x + t}} \), and when separating the variables, it should result in \( x e^{11x + t} dx = 9 dt \). 3. Integration: The solution then shows integration using integration by parts (IBP) on the left-hand side. This is a correct method, but the calculations themselves are flawed. It seems like the \( e^{-t} \) term is added without justification, and the integration by parts appears incorrect. 4. Solving for \( C \): The solution does attempt to solve for the constant \( C \) using the initial condition \( x(0) = 1 \). However, due to the previous mistakes, the equation for \( C \) will also be incorrect. 5. Evaluating at \( t_0 \): The solution does mention that the final step is to evaluate the solution at \( t_0 \), which is correct. However, again, due to the mistakes in integration and in finding \( C \), this step would also likely yield the wrong answer. I am working on a solution myself and I think I am almost there. I will post my thoughts on this once complete. With regards to this response, in my opinion, the approach is on the right track by identifying the type of ODE and attempting to use separation of variables, but the algebraic and calculus errors make the solution incorrect.
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09/24/23

Jonathan T.

Plug it into Wolfram.
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09/24/23

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