
Yefim S. answered 02/19/24
Math Tutor with Experience
dy/dx + y = xy3. Substitution v = y-2; dv/dx = - 2y-3dy/dx; dy/dx = - 1/2y3dv/dx; - 1/2y3dv/dx + y = xy3;
-1/2dv/dx + 1/y2 = x; dv/dx - 2v = - 2x; M = e∫-2dx = e-2x; (e-2x·v)' = - 2x; e-2x·v = - x2 + C; v = (- x2 + C)e2x;
y2 = e-2x/(C - x2)