
Jesse M. answered 04/29/23
Experienced Math and Science Tutor (AP, Honors, Regents, SAT/ACT)
There are a few steps to get the final answer, so if you would like me to explain how I went about balancing everything just let me know.
oxidation 1/2 reaction:
6I- --> 3I2 + 6e-
reduction 1/2 reaction:
ClO3-+ 6H+ + 6e- --> Cl- + 3H2O
Balanced Red/Ox Reaction
6I- + ClO3-+ 6H+ --> 3I2 + Cl- + 3H2O
Hope this helps :)